In: Statistics and Probability
A survey of 700 high school students in our stat showed that 216 felt unsafe in their local school. Construct a 95% confidence interval for the proportion of students who felt unsafe.
Solution :
Given that,
Point estimate = sample proportion =
= x / n = 216 / 700 = 0.309
1 -
= 1 - 0.309 = 0.691
Z/2
= 1.96
Margin of error = E = Z
/ 2 *
((
* (1 -
)) / n)
= 1.96 * (((0.309
* 0.691) / 700)
Margin of error = E = 0.034
A 95% confidence interval for population proportion p is ,
- E < p <
+ E
0.309 - 0.034 < p < 0.309 + 0.034
0.275 < p < 0.343
The 95% confidence interval for the population proportion p is : 0.275 , 0.343