The reaction glucose + ATP <=> glucose-1-phosphate + ADP has ΔG°' = -9.6 kJ mol-1. This...

The reaction glucose + ATP <=> glucose-1-phosphate + ADP has ΔG°' = -9.6 kJ mol-1. This is a coupled reaction which can be broken into two parts. The first part of the reaction is ATP + H2O <=> ADP + Pi, with ΔG°' = -30.5 kJ mol-1. The second part of the reaction is glucose + Pi <=> glucose-1-phosphate + H2O. Calculate the ΔG°' value for this reaction in kJ mol-1.

Solutions

Expert Solution

glucose + ATP <=> glucose-1-phosphate + ADP ΔG°' = -9.6 kJ mol-1.

ATP + H2O <=> ADP + Pi, ΔG°' = -30.5 kJ mol-1

(-) (-) (-) (-) (+)

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glucose + Pi <=> glucose-1-phosphate + H2O ΔG°' = 20.9Kj/mole

queen_honey_blossom answered 1 year ago

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