Question

An electron at ground state, absorbs the energy of a photon that has a frequency of 3.1573 x 10¹⁵/s, and jumps to the higher level. The same electron makes two more consecutive jumps. First, the electron jumps to another energy level by emitting a photon with a wavelength of 434.1 nm. This electron jumps immediately to the third energy level. Find the energy and the frequency of the photon which are the result of the third jump

Answer 1

434.1 nm = 434.1 x 10^-9 m

Frequency of first level jump = c/l

                                              = 3 x 10^8/434.1 x 10^-9 m       

                                              = 6.9 x 10^14 s-1

So,

frequency of third jump = 3.1573 x 10^15 - 6.9 x 10^14

                                      = 2.5 x 10^15 s-1

Energy of this third photon = 6.626 x 10^-34 x 2.5 x 10^15

                                           = 1.63 x 10^-18 J