Question

In: Chemistry

1. Calculate the value of work (w) for the internal energy change in the following reactions...

1. Calculate the value of work (w) for the internal energy change in the following reactions at 298 K. Which direction is the work being applied, by the system or on the system?

a) Ni(s) + 4 CO(g) .....> Ni(CO)4 (g)

b) 2 NO2(g)  N2O4(g)

2- For the following single step reaction, determine the reaction order overall and the orders of each reactant: N2H4(g) + H2(g)  2 NH3(g)

3-Draw and label a reaction energy diagram which is fast in its first step and slow in its second step, with an overall net release of energy.

Expert Solution

a) Ni(s) + 4 CO(g) .....> Ni(CO)4 (g)

per 1 mol of Ni(s)

Vinitial = 4 mol *22.4 L/mol = 89.6 L

Vfinal = 1 mol 22.4 L/mol = 22.4 L

dV = 22.4-89.6 = -67.2 L = -67.2 *10^-3 m3

P = 1 atm

W = -P*(dv)

W = -(101325)(-67.2 *10^-3) = 6809.04 J

b)

2 mol of gas --> 1 mol of gas

Vf = 1*22.4 L = 22.4 L

Vi = 2*22.4 = 44.8 L

dV = 22.4-44.8 = 22.4 L = 22.4*10^-3

W= -P*dV

W = -(101325)(-22.4*10^-3) = 2269.68 J

Q2.

if no data for rate of reaciton is added, we must assume elmetnary rate law

N2H4(g) + H2(g) -> 2 NH3(g)

Rate = k*[N2H4][H2]

1st order with respect to N2H2 ;1st order with respect to H2

overall order = 1+1 = 2nd

queen_honey_blossom answered 2 years ago

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