In: Statistics and Probability
Salaries of 38 college graduates who took a statistics course in college have a mean, x, of $66,100. Assuming a standard deviation, o, of $15,100, construct a 95% confidence interval for estimating the population mean u
$___<u<$___
Solution :
Given that,
= 66100
= 15100
n = 38
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (15100 / 38)
= 4801
At 95% confidence interval estimate of the population mean is,
- E < < + E
66100 - 4801 < < 66100 + 4801
$61299 < < $70901