In: Statistics and Probability
Salaries of 38 college graduates who took a statistics course in college have a? mean, x overbar ?, of $ 61 comma 500 . Assuming a standard? deviation, sigma ?, of ?$11 comma 382 ?, construct a 90 ?% confidence interval for estimating the population mean mu. (Round to the nearest integer as? needed.)
Solution :
Given that,
=
61,500
=
11,382
n = 38
At 90% confidence level the z is ,
= 1 - 90% =
1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 =
1.645
Margin of error = E = Z/2* (
/n)
= 1.645 * (11,382 / 38) = 3,040
At 90% confidence interval estimate of the population mean is,
- E <
<
+ E
61,500 - 3,040 < < 61,500 - 3,040
58,500 < < 64,500
(58,500 , 64.500)