In: Statistics and Probability
Salaries of 46 college graduates who took a statistics course in college have a mean, x overbarx, of $ 67,000. Assuming a standard deviation, sigmaσ, of $15,669, construct a 90% confidence interval for estimating the population mean muμ.
$_____ < μ < $________
(Round to the nearest integer as needed)
Solution :
Given that,
Point estimate = sample mean = = 67,000
Population standard deviation =
= 15,669,
Sample size = n =46
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
Z/2 = Z0.05 = 1.645 ( Using z table )
Margin of error = E = Z/2 * (
/n)
= 1.645* ( 15,669 / 46
)
= 3800
At 90% confidence interval
is,
- E <
<
+ E
67000 - 3800 < 67000 + 3800
$_63200____ < μ < $__70800______