In: Statistics and Probability
Salaries of 35 college graduates who took a statistics course in college have a mean, x overbarx, of $66, 200. Assuming a population standard deviation of $17,102, construct a 95% confidence interval for estimating the population meanμ.
$__________<μ<$______________
(Round to the nearest integer as needed.)
Solution :
Given that,
= $ 66, 200.
= $ 17,102
n = 35
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Margin of error = E = Z/2* (/n)
= 1.960 * (17.102 / 35 )
= 5.666
At 95% confidence interval estimate of the population mean is,
- E < < + E
66.200 - 5..666 < < 66.200 + 5.666
$ 60.534 < < $ 71.866