In: Statistics and Probability
Salaries of 42 college graduates who took a statistics course in college have a mean, x overbar, of $ 68,500. Assuming a standard deviation, σ, of $13,898, construct a 99% confidence interval for estimating the population mean μ.
$___< μ < $ ___
(Round to the nearest integer as needed.)
Given that,
= 68500
= 13898
n = 42
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 =
0.01
/ 2 = 0.01 / 2 = 0.005
Z/2
= Z0.005 = 2.576
Margin of error = E = Z/2*
(
/
n)
=2.576 * (13898 /
42)
= 5524
At 99% confidence interval estimate of the population mean is,
- E <
<
+ E
13898 - 5524 <
< 13898 + 5524
8374<
< 19422
(8374, 19422)