If 5.00 mL of H2C2O4(0.8 M) are diluted to 100.0 mL, what is the concentration of...

If 5.00 mL of H2C2O4(0.8 M) are diluted to 100.0 mL, what is the concentration of the new solution?

Expert Solution

We need to apply dilution law, which is based on the mass conservation principle

initial mass = final mass

this apply for moles as weel ( if there is no reaction, which is the case )

mol of A initially = mol of A finally

or, for this case

moles of A in stock = moles of A in diluted solution

Recall that

mol of A = Molarity of A * Volume of A

then

moles of A in stock = moles of A in diluted solution

Molarity of A in stock * Volume of A in stock = Molarity of A in diluted solution* Volume of A in diluted solution

Now, substitute known data

0.8 M * 5 mL = M2*100 mL

M2 = 0.8*5/100

M2 = 0.04 mol of H2C2O4 per liter

queen_honey_blossom answered 2 years ago

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