In: Statistics and Probability
A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 3 points with 99% confidence assuming s=12.5 based on earlier studies? Suppose the doctor would be content with 90% confidence. How does the decrease in confidence affect the sample size required?
for 99% confidence interval:
for 99 % CI value of z= | 2.576 |
standard deviation σ= | 12.50 |
margin of error E = | 3 |
required sample size n=(zσ/E)2 = | 116.0 |
for 90% confidence interval:
for 90 % CI value of z= | 1.645 |
standard deviation σ= | 12.50 |
margin of error E = | 3 |
required sample size n=(zσ/E)2 = | 47.0 |
hence decreasing confidence interval to 90% will decrease the requirement of sample size.