Question

In: Statistics and Probability

The following data were collected from a repeated-measures study: Determine if there are any significant differences...

The following data were collected from a repeated-measures study:

Determine if there are any significant differences among the four treatments. Use a .05 level of significance.

Remember to;

1) State the null hypothesis,

2) Show all of your calculations,

3) Make a decision about your null hypothesis,

4) Make a conclusion including an APA format summary of your findings (include a measure of effect size if necessary), and

5) Indicate what you would do next given your findings.

Participant

Treatments

A

B

C

D

X2 = 332

G = 60

1

2

3

4

6

4

4

10

3

4

2

7

3

2

0

7

0

2

2

4

T = 24

SS = 24

T = 16

SS = 14

T = 12

SS = 26

T = 8

SS = 8

Solutions

Expert Solution

1)

Ho: µ1=µ2=µ3=µ4
H1: not all means are equal

2)

treatment A B C D
count, ni = 4 4 4 4
mean , x̅ i = 6.000 4.00 3.00 2.00
std. dev., si = 2.828 2.160 2.944 1.633
sample variances, si^2 = 8.000 4.667 8.667 2.667
total sum 24 16 12 8 60 (grand sum)
grand mean , x̅̅ = Σni*x̅i/Σni =   3.75
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² 5.063 0.063 0.563 3.063
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 20.250 0.250 2.250 12.250 35
SS(within ) = SSW = Σ(n-1)s² = 24.000 14.000 26.000 8.000 72.000

no. of treatment , k =   4
df between = k-1 =    3
N = Σn =   16
df within = N-k =   12
  
mean square between groups , MSB = SSB/k-1 =    11.6667
  
mean square within groups , MSW = SSW/N-k =    6.0000
  
F-stat = MSB/MSW =    1.9444
P value =   0.1763

3)

p-value>α , do not reject null hypothesis

4)

there is no significant difference among means of different treatment F(3,12) = 1.94,p>0.10

5) there is no steps will be taken forward because null hypothesis is not rejected


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