In: Statistics and Probability
Suppose that 57% of all college seniors have a job prior to graduation. If a random sample of 80 college seniors is taken, approximate the probability that more than 46 have a job prior to graduation. Use the normal approximation to the binomial with a correction for continuity.
Let X be the number of college seniors who have a job prior to
graduation
p = probability of selecting a college senior having a job =
0.57
n = 80
X follows Binomial distribution with n = 80 and p =
0.57
Using Normal Approximation for Binomial, we know
X ~ Normal distribution with mean μ=np and standard deviation
σ=sqrt(npq)
q = 1-p = 1-0.57 = 0.43
μ = np = 80*0.57 = 45.6
σ =sqrt(npq) = sqrt(80*0.57*0.43) = 4.4281
we get
μ = 45.6
σ = 4.4281
To find P(more than 46 have a job prior to
graduation)
that is to find P(X > 46)
With Continuity Correction
P(X > 46) = 1 - P(X ≤ 46)
= 1 - P(X ≤ 46.5)
…adding 0.5 for continuity correction
Using Excel function NORM.DIST to find the probability, we
get
P(X > 46) = 1 - NORM.DIST(46.5, 45.6, 4.4281, TRUE)
= 1 - 0.5805
= 0.4195
P(more than 46 have a job prior to graduation) =