What would be the concentration of chromate ion, CrO42-, in a saturated solution of CaCrO4 (ksp=7.1x10^-4)...

What would be the concentration of chromate ion, CrO42-, in a saturated solution of CaCrO4 (ksp=7.1x10^-4) *Please explain what you're doing and why*

Expert Solution

CaCrO4 ----------------> Ca+2 + CrO42-

S S

Ksp = [Ca+2][CrO4-]

7.1x10^-4 = S^2

S = 0.0266 M

concentration of chromate ion = 0.027 M

queen_honey_blossom answered 3 years ago

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