Question

what is the molarity concentration of lead cation in a saturated solution of lead sulfate? Ksp(PbSO4)= 6.3x10^-7 and what is the solubility of PbSO4 in g/ml?

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Answer 1

    PbSO4 ------> Pb⁺² + So4^2-

                            s           s

Ksp = [Pb⁺²][So4^2-]

6.3x10^-7       = s*s

s²                 = 6.7*10^-7

s                    = 8.185*10^-4 M

[Pb+2]   = 8.18*10^-4 M

molarity of PbSO4 = 8.185*10^-4 mole/L

= 8.185*10^-4mole/L *303.26g/mole

                                = 2482.18g/L

                               = 2482.18g/1000ml

                               = 2.48218g/ml