In: Chemistry
pH = 0.5
[H2S] = 0.1 mol/L = 0.1M
Initial 0.1 0 0
Final (0.1 - x) (2x + 0.3010) x
assuming 0.1 - x = 0.1 and (2x + 0.3010 = 0.3010) [ since x is very small value]
Hence the sulfide ion concentration is equal to 1.214 * 10^(-21)