In: Statistics and Probability
The label on a “two liter” bottle of soft drink indicates that it is supposed to contain 2000 milliliters (ml). However, there is some variation due to the production process; this process is known to be normally distributed with a standard deviation of 20 ml. A government inspector wants to ensure that the public is not cheated by purchasing underfilled containers. A random sample of nine containers was selected; the measurement results were: 1995, 1960, 2005, 2008, 1997, 1992, 1986, 1972 and 2013 ml. Is this convincing evidence (using a 5% significance level, α = .05) that the containers are underfilled?
a) State (using symbols) the null and alternative hypotheses.
b) Identify and calculate the test statistic.
c) Determine the P-value.
d) Reach a decision and present the conclusion.
Null Hypothesis, 2000
Alternative Hypothesis, 2000
Here, sample mean, 1992, Population std. dev., 20, Sample size, n = 9
Here the significance level, 0.05. This is right tailed test; hence rejection region lies to the right. -1.64 i.e. P(z < -1.64) = 0.05
Reject H0 if test statistic, z < -1.64
Test statistic,
z = (1992 - 2000)/(20/sqrt(9))
z = -1.2
P-value = P(z < -1.2)
P-value = 0.1151
As p-value is greater than 0.05, fail to reject H0
There is not sufficient evidence to conclude that the mean is less than 2000 ml (i.e. underfilling)