Question

In: Chemistry

If delta rG for the following reaction is -1880 kJ, calculate Ecell. How many electrons are...

If delta rG for the following reaction is -1880 kJ, calculate Ecell. How many electrons are transferred in this equation?

2MnO4- (aq) + 5Fe (s) + 16H+ (aq) ----> 2 Mn2+ (aq) + 5 Fe2+ (aq) +8H20 (l)

(I am trying to find n electrons in order to plug into the equation: Ecell=DeltaG/nF)

Solutions

Expert Solution

Oxidation number of each element in MnO4-1 is

O=-2

Mn=+7

Oxidation number of each element in Fe is

Fe=0

Oxidation number of each element in Mn+2 is

Mn=+2

Oxidation number of each element in Fe+2 is

Fe=+2

Oxidation number of each element in reactant is

O=-2

Mn=+7

Fe=0

Oxidation number of each element in product is

Mn=+2

Fe=+2

Mn in MnO4- has oxidation state of +7

Mn in Mn+2 has oxidation state of +2

So, Mn in MnO4- is reduced to Mn+2

Number of electron transferred per Mn = 5

there are 2 Mn.

So, number of electron = 10

Fe in Fe has oxidation state of 0

Fe in Fe+2 has oxidation state of +2

So, Fe in Fe is oxidised to Fe+2

Number of electron transferred per Fe = 2

there are 5 Fe.

So, number of electron = 10

Either way we can find out the number of electrons

It is 10


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