Question

In: Statistics and Probability

Here are the summary statistics for randomly selected weights of newborn girls: n=237, mean=33.8 hg, and...

Here are the summary statistics for randomly selected weights of newborn girls: n=237, mean=33.8 hg, and s=6.2 hg. Construct a confidence interval estimate of the mean. Use a 90% confidence level

Expert Solution

solution

Given that,

= 33.8

s =6.2

n = 237

Degrees of freedom = df = n - 1 =237 - 1 = 236

At 90% confidence level the t is ,

= 1 - 90% = 1 - 0.90 = 0.1

/ 2 = 0.1 / 2 = 0.05

t /2,df = t0.05,236 = 1.651 ( using student t table)

Margin of error = E = t/2,df * (s / $\sqrt$ n)

= 1.651* ( 6.2/ $\sqrt$ 237) = 0.66

The 90% confidence interval is,

- E < < + E

33.8-0.66 < < 33.8+ 0.66

33.14 < < 34.46

(33.14 , 34.46 )

orchestra answered 1 year ago

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