In: Statistics and Probability
Q7. Here are summary statistics for randomly selected weights of newborn girls: n=210, x overbarx=28.9 hg, s=6.3hg. Construct a confidence interval estimate of the mean. Use a 99% confidence level. Are these results very different from the confidence interval 27.0 hgless than
What is the confidence interval for the population mean muμ?
____hgless than
std dev , s =    6.3000
Sample Size ,   n =    210
Sample Mean,    x̅ =   28.9000
Level of Significance ,    α =   
0.01          
'   '   '      
   
z value=   z α/2=   2.5758   [Excel
formula =NORMSINV(α/2) ]      
          
       
Standard Error , SE = s/√n =   6.300   /
√   210   =   0.4347
margin of error, E=Z*SE =   2.5758  
*   0.435   =   1.120
          
       
confidence interval is       
           
Interval Lower Limit = x̅ - E =    28.90  
-   1.120   =   27.7802
Interval Upper Limit = x̅ + E =    28.90  
-   1.120   =   30.0198
99%   confidence interval is (   27.8
< µ <   30.0 )