In: Chemistry
A sample of THAM primary standard base weighed 0.9180 grams. After dissolving in 100ml deionized water and adding four drops of brom-cresol-green indicator, an HCl solution was added gradually until a definite color change was observed. At this point, 28.20 ml of HCL solution had been drained from the buret. Using the equation for the overall reaction, calculate the molarity of the HCl
THAM base molar mass = 121.14 g/mol
THAM base moles = mass / molar mass
= 0.9810 / 121.14
= 0.00809
HCl moles = THAM base moles
= 0.00809
volume of HCl = 28.20 ml = 0.0282
molarity of HCl = moles / volume
= 0.00809 / 0.0282
= 0.287 M
molarity of HCl =0.287 M