Question

In: Chemistry

A sample of THAM primary standard base weighed 0.9180 grams. After dissolving in 100ml deionized water...

A sample of THAM primary standard base weighed 0.9180 grams. After dissolving in 100ml deionized water and adding four drops of brom-cresol-green indicator, an HCl solution was added gradually until a definite color change was observed. At this point, 28.20 ml of HCL solution had been drained from the buret. Using the equation for the overall reaction, calculate the molarity of the HCl

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Expert Solution

THAM base molar mass = 121.14 g/mol

THAM base moles = mass / molar mass

                               = 0.9810 / 121.14

                               = 0.00809

HCl moles = THAM base moles

                  = 0.00809

volume of HCl = 28.20 ml = 0.0282

molarity of HCl = moles / volume

                         = 0.00809 / 0.0282

                         = 0.287 M

molarity of HCl =0.287 M


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