a solution is prepared by dissolving 26.6 grams of glucose in 0.949 kilogramos of water. the...

a solution is prepared by dissolving 26.6 grams of glucose in 0.949 kilogramos of water. the final volume of the solution is 738 mililiters. calculate mole fraction

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Expert Solution

no of moles of glucose = W/G.M.Wt = 26.6/180 = 0.148 moles

no of moles of water = W/G.M.Wt = 949/18 = 52.72 moles

total no of moles = 0.148+52.72 = 52.868

mole fraction of glucose = no of moles of glucose/ total no of moles

= 0.148/52.868 = 0.0028

mole fraction of water = no of moles of water/ total no of moles

= 52.72/52.868 = 0.9972

queen_honey_blossom answered 1 year ago

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