a solution is prepared by dissolving 26.6 grams of glucose in 0.949 kilogramos of water. the...

a solution is prepared by dissolving 26.6 grams of glucose in 0.949 kilogramos of water. the final volume of the solution is 738 mililiters. calculate mole fraction

Expert Solution

no of moles of glucose = W/G.M.Wt = 26.6/180 = 0.148 moles

no of moles of water = W/G.M.Wt = 949/18 = 52.72 moles

total no of moles = 0.148+52.72 = 52.868

mole fraction of glucose = no of moles of glucose/ total no of moles

= 0.148/52.868 = 0.0028

mole fraction of water = no of moles of water/ total no of moles

= 52.72/52.868 = 0.9972

queen_honey_blossom answered 2 years ago

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