The compound K2SO4 has solubility of 15 grams in 100mL of water. How many milliliters of...

The compound K2SO4 has solubility of 15 grams in 100mL of water. How many milliliters of water are required to dissolve 53 grams of K2SO4?

Expert Solution

15 g of K₂SO₄ require 100mL of water

Therefore 53 g of K₂SO₄ will require 100 mL x 53 g / 15 g of water = 353.3mL of water

The volume of water required to dissolve 53 grams of K2SO4 = 353.3 mL

ALTRNATE METHOD

Mass of K₂SO₄ Volume of water

15 g 100mL

53 g x

= 353.3 mL

The volume of water required to dissolve 53 grams of K2SO4 = 353.3 mL

queen_honey_blossom answered 7 months ago

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