In: Chemistry
The compound K2SO4 has solubility of 15 grams in 100mL of water. How many milliliters of water are required to dissolve 53 grams of K2SO4?
15 g of K2SO4 require 100mL of water
Therefore 53 g of K2SO4 will require 100 mL x 53 g / 15 g of water = 353.3mL of water
The volume of water required to dissolve 53 grams of K2SO4 = 353.3 mL
ALTRNATE METHOD
Mass of K2SO4 Volume of water
15 g 100mL
53 g x
= 353.3 mL
The volume of water required to dissolve 53 grams of K2SO4 = 353.3 mL