Question

In: Chemistry

A student ran two separate substitution reactions, Reaction A and Reaction B, in lab that utilized...

A student ran two separate substitution reactions, Reaction A and Reaction B, in lab that utilized an alkyl halide and a nucleophile. However, he did not know if the reactions proceeded through an SN1 or SN2 mechanism. To determine the mechanism for both reactions, the student increased the concentration of the nucleophile in Reactions A and B. The rate of reaction for Reaction A increased. The rate of reaction for Reaction B remained the same.

(a) Which reaction is the SN1 reaction? (1 pt)

(b) Which reaction is the SN2 reaction? (1 pt)

(c) Explain both of your choices. (4 pts)

Solutions

Expert Solution

Condition for SN1 reaction:

SN1 reaction is an unimolecular and hence, a first order reaction. So, only substrate such as electrophile affects the reaction rate.

For reaction:   RX    + Y   ---> RY   +   X

The reaction rate is expressed as rate = k [RX]

This reaction has two steps.

Intermediate is a stable carbocation which is formed during the course of reaction.

This generally has two transition states as it is a two step reaction.

The stability of carbocation is the key factor of the reaction. Hence, reactivity of alkyl halides are as: 3o > 2o > 1o

For this reaction, weak or neutral nucleophiles are sufficient.

Conditions for SN2 reaction:

It is a bimolecular or a second order reaction. Hence, both substrate such as electrophile and nucleophile affect the rate of reaction

For reaction:   RX    + Y   ---> RY   +   X

The reaction rate is expressed as rate = k[RX][Y]

This reaction has only one step.

This reaction goes through a transition state, there is no intermediate cation formation.

Presence of steric hindrance affect the reaction as transition state becomes more crowded. Hence reactivity of alkyl halides are as: 1o > 2o > 3o

In this pathway strong nucleophiles are desired.

Based on these conditions:

(a) Reaction B is SN1 reaction as there is no effect of nucleophile concentration.

(b) Reaction A is SN2 reaction as there is an increase in rate of reaction as increasing nucleophile increases rate of reaction.

(c) The conditions for both type of reactions are explained in above points.


Related Solutions

Separate the following redox reactions into half-reactions, and label each half-reaction as oxidation or reduction. Part...
Separate the following redox reactions into half-reactions, and label each half-reaction as oxidation or reduction. Part A Oxidation half-reaction for 2Li(s)+2H+(aq)→2Li+(aq)+H2(g). Express your answer as a chemical equation. Identify all of the phases in your answer. SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining; no points deducted Part B Reduction half-reaction for 2Li(s)+2H+(aq)→2Li+(aq)+H2(g). Express your answer as a chemical equation. Identify all of the phases in your answer. SubmitMy AnswersGive Up Part C Oxidation half-reaction for 2Ag+(aq)+Be(s)→Be2+(aq)+2Ag(s). Express your...
A student ran the following reaction in the laboratory at 445 K : PCl5(g)-------> PCl3(g) +...
A student ran the following reaction in the laboratory at 445 K : PCl5(g)-------> PCl3(g) + Cl2(g) When she introduced 1.28 moles of PCl5(g) into a 1.00 liter container, she found the equilibrium concentration of PCl5(g) to be 1.24 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
Separate this redox reaction into its component half-reactions. O2 + --> 2 Oxidation half reaction? Reduction...
Separate this redox reaction into its component half-reactions. O2 + --> 2 Oxidation half reaction? Reduction half reaction?
1. A student ran the following reaction in the laboratory at 582 K: CO(g) + Cl2(g)...
1. A student ran the following reaction in the laboratory at 582 K: CO(g) + Cl2(g)      COCl2(g) When she introduced 0.380 moles of CO(g) and 0.403 moles of Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of COCl2(g) to be 0.342 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. 2. The equilibrium constant, Kc, for the following reaction is 1.29×10-3 at 540 K. COCl2(g) CO(g) + Cl2(g) When a sufficiently large sample of COCl2(g)...
Propose a nucleophilic aromatic substitution mechanisms for the reactions of a) 2,4-dinitrochlorobenzene + sodium methoxide b)...
Propose a nucleophilic aromatic substitution mechanisms for the reactions of a) 2,4-dinitrochlorobenzene + sodium methoxide b) 2,4-dimethylchlorobenzene + sodium hydroxide, 350 degrees C c) p-nitrobromobenzene + methylamine d) 2,4-dinitrochlorobenzene
A student ran the following reaction in the laboratory at 684 K: N2(g) + 3H2(g) 2NH3(g)...
A student ran the following reaction in the laboratory at 684 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.26×10-2 moles of N2(g) and 6.07×10-2 moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of H2(g) to be 5.83×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = __
-A student ran the following reaction in the laboratory at 1143 K: 2SO2(g) + O2(g) 2SO3(g)...
-A student ran the following reaction in the laboratory at 1143 K: 2SO2(g) + O2(g) 2SO3(g) When she introduced 8.19×10-2 moles of SO2(g) and 8.56×10-2 moles of O2(g) into a 1.00 liter container, she found the equilibrium concentration of O2(g) to be 6.08×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =____________ -A student ran the following reaction in the laboratory at 363 K: CH4(g) + CCl4(g)      2CH2Cl2(g) When she introduced 4.64×10-2 moles of CH4(g) and...
A student ran the folllowing reaction in the laboratory at 661 K: 2NH3(g) N2(g) + 3H2(g)...
A student ran the folllowing reaction in the laboratory at 661 K: 2NH3(g) N2(g) + 3H2(g) When she introduced NH3(g) at a pressure of 0.597 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of H2(g) to be 0.879 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction.
A student ran the following reaction in the laboratory at 720 K: H2(g) + I2(g) 2HI(g)...
A student ran the following reaction in the laboratory at 720 K: H2(g) + I2(g) 2HI(g) When she introduced 0.189 moles of H2(g) and 0.218 moles of I2(g) into a 1.00 liter container, she found the equilibrium concentration of I2(g) to be 6.05×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 291 K: 2CH2Cl2(g) CH4(g) + CCl4(g)...
A student ran the following reaction in the laboratory at 291 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When she introduced 6.63×10-2 moles of CH2Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of CH2Cl2(g) to be 4.92×10-3 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = _____
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT