In: Statistics and Probability
Let p be the true proportion of patients treated with stent implantation experienced another cardiovascular event within four years of their surgery
Null Hypothesis H0: p = 0.156
Alternative Hypothesis H0: p > 0.156
np(1-p) = 1083 * 0.156 * (1 - 0.156) = 142.5921
Since, np(1-p) > 10, the sample size is large enough to assume that the sampling distribution of proportion is normal and we can use one sample z test.
Significance level = 0.01
Decision - Reject null hypothesis H0 if p-value is less then 0.01
Standard error of mean, SE = = 0.01102603
Sample proportion, = 187/1083 = 0.1726685
Test statistic, z = ( - p) / SE = (0.1726685 - 0.156) / 0.01102603 = 1.51
P-value = P(z > 1.51) = 0.0655
Since, p-value is greater than 0.05 significance level, we fail to reject null hypothesis H0 and conclude that there is no strong evidence from the sample data that true proportion of patients treated with stent implantation experienced another cardiovascular event within four years of their surgery is greater than 0.156. Hence we cannot significantly conclude that the stent implantation was less effective for clearing arteries of plaque than medical therapy alone.