In: Statistics and Probability
Salaries of 47 college graduates who took a statistics course in college have a mean, overbar x, of $65,600. Assuming a standard deviation, σ, of $12,213, construct a 95% confidence interval for estimating the population mean μ.
$__ < μ < $ __
Solution :
Given that,
Point estimate = sample mean = =65600
Population standard deviation =
= 12213
Sample size n =47
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 1.96 * (12213 / 47 )
E= 3491.6403
At 95% confidence interval estimate of the population mean
is,
- E <
<
+ E
65600 -3491.6403 <
<65600 + 3491.6403
62108.3597 <
< 69091.6403
( $ 62108.3597 <
< $69091.6403)