In: Statistics and Probability
In a study, 1319 schoolchildren at the age of 12 were random selected to be questioned on the prevalence of symptoms of severe cold. Another 1319 schoolchildren at age 14 were random selected to be questioned on the prevalence of symptoms of severe cold. For schoolchildren of age 12, 356 children were reported to have severe colds in the past 12 months, for schoolchildren of age 14, 468 were reported to have severe colds in the past 12 months. Is there an association between the prevalence of severe cold and the age of 12 and 14?
Please conduct a hypothesis testing using the Chi-square test to justify your conclusion.
Solution | ||||||||
CALCULATION TABLE | ||||||||
COLD | NOT COLD | TOTAL | ||||||
AGE 12 | 356 | 963 | 1319 | |||||
AGE 14 | 468 | 851 | 1319 | |||||
TOTAL | 824 | 1814 | 2638 | |||||
EXPECTED FREQENCY | E1= | 1369*824/2638 | ||||||
412 | ||||||||
O= | OBSERVED FREQUENCY | |||||||
E= | EXPECTED FREQENCY | |||||||
DF= | (R-1)(C-1) | |||||||
DF= | (2-1)(2-1) | |||||||
DF= | 1 | |||||||
LEVEL | 5% | |||||||
H0: | There is no association between the prevalence of severe cold children of the age of 12 and 14 | |||||||
H1: | There is an association between the prevalence of severe cold children of the age of 12 and 14 | |||||||
CALCULATION TABLE | TOTAL | |||||||
O | 356 | 963 | 468 | 851 | 2638 | |||
E | 412 | 907 | 412 | 907 | 2638 | |||
O-E | -56 | 56 | 56 | -56 | 0 | |||
(O-E)2/E | 7.6116505 | 3.4575524 | 7.61165049 | 3.45755237 | 22.1384057 | |||
(TEST STATISTICS) | ||||||||
CHI SQUARE=22.1384 | ||||||||
CRITICAL VALUE OF CHI SQUARE = | 3.84 | |||||||
CONCLUSION : | ||||||||
CHI SQUARE=22.1384 | (TEST STATISTICS) is greater than the critical value (3.84) | |||||||
So we reject null hypothesis H0 | ||||||||
and conclude that | ||||||||
There is an association between the prevalence of severe cold children of the age of 12 and 14 | ||||||||