Question

In: Statistics and Probability

Giving a test to a group of students, the grades and gender are summarized below A...

Giving a test to a group of students, the grades and gender are summarized below

A B C Total
Male 3 12 6 21
Female 10 2 5 17
Total 13 14 11 38



Let ππ represent the percentage of all male students who would receive a grade of C on this test. Use a 80% confidence interval to estimate p to three decimal places.

Enter your answer as a tri-linear inequality using decimals (not percents).

< p <

Solutions

Expert Solution

Total number of students = 13+141+138 = 292

P[  percentage of all male students who would receive a grade of C on this test ] = 21/292

We need to construct the 80% confidence interval for the population proportion. We have been provided with the following information about the number of favorable cases:

Favorable Cases X = 21
Sample Size N = 292

The sample proportion is computed as follows, based on the sample size N = 292 and the number of favorable cases X = 21    

The critical value for =0.2 is z_c = 1.282. The corresponding confidence interval is computed as shown below:

Therefore, based on the data provided, the 80% confidence interval for the population proportion is 0.053 < p < 0.091 , which indicates that we are 80\%80% confident that the true population proportion p is contained by the interval (0.053, 0.091)(0.053,0.091).


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