In: Statistics and Probability
Giving a test to a group of students, the grades and gender are summarized below
A B C Total
Male 18 16 6 40
Female 13 19 15 47
Total 31 35 21 87
Let p represent the population proportion of all female students who received a grade of B on this test. Use a 99% confidence interval to estimate p to four decimal places if possible. < p <
Level of Significance, α =
0.01
Number of Items of Interest, x =
19
Sample Size, n = 47
Sample Proportion , p̂ = x/n =
0.404
z -value = Zα/2 = 2.576 [excel
formula =NORMSINV(α/2)]
Standard Error , SE = √[p̂(1-p̂)/n] =
0.0716
margin of error , E = Z*SE = 2.576
* 0.0716 = 0.1844
99% Confidence Interval is
Interval Lower Limit = p̂ - E = 0.404
- 0.1844 = 0.2199
Interval Upper Limit = p̂ + E = 0.404
+ 0.1844 = 0.5886
99% confidence interval is (
0.2199 < p < 0.5886
)
................
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