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Describe how to prepare exactly 100.0 mL of 1.00 M HCL from 12.1 M reagent

Describe how to prepare exactly 100.0 mL of 1.00 M HCL from 12.1 M reagent

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Expert Solution

intial                                                           final

M1 = 1M                                                     M2 = 12.1M

V1 = 100ml                                               V2 =

       M1V1   =   M2V2

        V2     = M1V1/M2

                = 1*100/12.1   = 8.264 ml >>>>answer

queen_honey_blossom answered 1 year ago
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