How many milliliters of 11.0 M HCl(aq) are needed to prepare 455.0 mL of 1.00 M...

How many milliliters of 11.0 M HCl(aq) are needed to prepare 455.0 mL of 1.00 M HCl(aq)?

Expert Solution

Before dilution After dilution

M1 = 11M M2 = 1M

V1 = V2 = 455ml

M1V1 = M2V2

V1 = M2V2/M1

= 1*455/11 = 41.36ml

before dilution volume of HCl = 41.36ml >>>>answer

queen_honey_blossom answered 1 year ago

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