In: Chemistry
How many milliliters of 11.0 M HCl(aq) are needed to prepare 455.0 mL of 1.00 M HCl(aq)?
Before dilution After dilution
M1 = 11M M2 = 1M
V1 = V2 = 455ml
M1V1 = M2V2
V1 = M2V2/M1
= 1*455/11 = 41.36ml
before dilution volume of HCl = 41.36ml >>>>answer