A student added 50.0 mL of an NaOH solution to 100.0 mL of 0.300 M HCl....

A student added 50.0 mL of an NaOH solution to 100.0 mL of 0.300 M HCl. The solution was then treated with an excess of aqueous chromium(III) nitrate, resulting in formation of 2.36 g of precipitate. Determine the concentration of the solution.

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Expert Solution

concentration of the NaOH solution = 1.98 M

Please find the explanation given below

queen_honey_blossom answered 1 year ago

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