Solve the initial value problem: y'' + 4y' + 4y = 0; y(0) = 1,
y'(0) = 0.
Solve without the Laplace Transform, first, and then with the
Laplace Transform.
A) Solve the initial value problem:
8x−4y√(x^2+1) * dy/dx=0
y(0)=−8
y(x)=
B) Find the function y=y(x) (for x>0 ) which
satisfies the separable differential equation
dy/dx=(10+16x)/xy^2 ; x>0
with the initial condition y(1)=2
y=
C) Find the solution to the differential equation
dy/dt=0.2(y−150)
if y=30 when t=0
y=
Solve the given initial-value problem. y'' + 4y' + 4y = (5 +
x)e^(−2x) y(0) = 3, y'(0) = 6
Arrived at answer
y(x)=3e^{-2x}+12xe^{-2x}+(15/2}x^2e^{-2x}+(5/6)x^3e^{-2x) by using
variation of parameters but it was incorrect.