Let's say for a chlorophyll solution we found the absorbance, and use d that with Beer's...

Let's say for a chlorophyll solution we found the absorbance, and use d that with Beer's law to find the concentration. How come that concentration is different if we find the concentration of the same chlorophyll solution using the fluorescence?

Expert Solution

According to Beer's law, we can express the absorbance of light by a sample solution can be specified as shown below.

A = 'cl, where ' = /2.303 ( = molar absorption coefficient and ' = molar extinction coefficient), c = concentration of the sample soluion and l = path length of sample

The intensity of fluorescence emission of weakly absorbing, dilute samples can be expressed as shown below.

F = I₀(cl), where I₀ = intensity of incident light and = quantum efficiency.

The above equation holds for dilute solutions only.

Hence, the concentration of the chlorophyll solution found by Beer's law can be much higher when compared to that found using the fluorescence.

queen_honey_blossom answered 2 years ago

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Let's say for a chlorophyll solution we found the absorbance, and use d that with Beer's...

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