Question

So let's say I got 60% in test. then we have to divide that into 2 so now I got 30% and then we have to add 50% to it. So my final test marks is 80%.

write a function in C++ that takes a map<string, int> which represents a students name to their test marks and returns a map<string, double> which represents the upgraded marks.
Please write this function without using any for or while loops.

Example:

Input: {{"Ved", 10}, {"Mike", 80}, {"Jack", 20}, {"Smith", 25}}

Output: {{"Ved", 55}, {"Mike", 90}, {"Jack", 60}, {"Smith", 62.5}}

Code in C++ ONLY, without using LOOPS.

Thank you!

Answer 1

#include <iostream>
#include <iterator>
#include <map>

using namespace std;
map<string, int> mark;
map<string,double> m2;
map<string, int>::iterator itr;
//HERE IS THE FUNCTION
map<string,double> marks_upgrades()
{
    if (itr==mark.end())
    {
          return m2;
    }
    else
    {
        m2[itr->first]=(double)itr->second/2+50.0;
        itr++;
        m2= marks_upgrades();
        return m2;
    }
}

int main()
{
    mark.insert(pair<string, int>("Ved", 10));
    mark.insert(pair<string, int>("Mike", 80));
    mark.insert(pair<string, int>("Jack", 20));
    mark.insert(pair<string, int>("Smith", 25));
    itr=mark.begin();
    //FUNCTION CALL TO MAKE THE CHANGES IN THE MARKS
    m2=marks_upgrades();

    itr=mark.begin();

    cout<<"\n";
    for (itr = mark.begin(); itr != mark.end(); ++itr) {
        cout << itr->first
             << '\t' << itr->second << '\n';
    }
    map<string, double>::iterator itr1;
    cout<<"\n";
    for (itr1 = m2.begin(); itr1 != m2.end(); ++itr1) {
        cout << itr1->first
             << '\t' << itr1->second << '\n';
    }
    return 0;
}

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