Let's assume our class represents a normal population with a known mean of 90 and population...

Let's assume our class represents a normal population with a known mean of 90 and population standard deviation 2. There are 100 students in the class. a. Construct the 95% confidence interval for the population mean. b. Interpret what this means. c. A few students have come in. Now we cannot assume normality and we don't know the population standard deviation. Let the sample mean = 90 and sample standard deviation = 3. Let's make the sample size 20. We can assume alpha to be .05. Construct the 95% confidence interval assuming this new information

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orchestra answered 2 years ago

Let's assume our class represents a normal population with a known mean of 90 and population...

Let's assume our class represents a normal population with a known mean of 90 and population standard deviation 2. There are 100 students in the class. a. Construct the 95% confidence interval for the population mean. b. Interpret what this means. c. A few students have come in. Now we cannot assume normality and we don't know the population standard deviation. Let the sample mean = 90 and sample standard deviation = 3. Let's make the sample size 20. We...

Let's assume our class represents a normal population with a known mean of 95 and population...

Let's assume our class represents a normal population with a known mean of 95 and population standard deviation 3. There are 120 students in the class. a. Construct the 95% confidence interval for the population mean. b. Interpret what this means. c. A few students have come in. Now we cannot assume normality and we don't know the population standard deviation. Let the sample mean = 90 and sample standard deviation = 2. Let's make the sample size 20. We...

For normal population with known standard deviation, the x% confidence interval for the population mean µ...

For normal population with known standard deviation, the x% confidence interval for the population mean µ has a lower end point (z times the standard error) below the sample mean and a upper end point (z times the standard error) above the sample mean. That is, the x% CI is given as Sample mean ± z *standard error For 95% CI, the value for z is Answer 1Choose...2.581.6451.280.9751.96 For 80% CI, the value for z is Answer 2Choose...2.581.6451.280.9751.96 For 90%...

Assume a normal distribution with a mean of 90 and a standard deviation of 7. what...

Assume a normal distribution with a mean of 90 and a standard deviation of 7. what limits would include the middle 75% of the cases.

Let's assume, for instance, that you are drawing a sample from a normal distribution with mean=0,...

Let's assume, for instance, that you are drawing a sample from a normal distribution with mean=0, and then you use t-test to assess whether the mean of the sample you just drawn is "significantly different" from zero. Then you repeat this procedure (draw-run t-test) many times. Will at least some of your samples (drawn from normal with known mean=0!) look significant? Why? Isn't p-value supposed to tell us good findings from the bad and true hypotheses from false ones? How...

Suppose that Xi’s are coming from a normal population with a mean μ =10 and known...

Suppose that Xi’s are coming from a normal population with a mean μ =10 and known variance σ=2. Generate 100 samples of n=50 observations coming from the population of interest. Please, construct the 90% confidence interval for each sample and report the number of confidence intervals that include the mean μ value. Compare this number with the expected number of confidence intervals that include the mean μ value. please help me. i colud not solve it

(Topic: Confidence Interval Estimation for the Mean of a Normal Distribution: Population Variance Known) The number...

(Topic: Confidence Interval Estimation for the Mean of a Normal Distribution: Population Variance Known) The number of bolts produced each hour from a particular machine is normally distributed with a standard deviation of 7.4. For a random sample of 15 hours, the average number of bolts produced was 587.3. Find the upper and lower confidence limits of a 98% confidence interval for the population mean number of bolts produced per hour. Find the answer by hand calculation. Find the answer...

A confidence interval for the population mean when the population follows the normal distribution and the population standard deviation is known is computed by? Provide examples.

Question 3 A confidence interval for the population mean when the population follows the normal distribution and the population standard deviation is known is computed by? Provide examples. Question 6 What are the factors that determine the sample size? How is sample size calculated for estimating the population mean? Provide examples

Assume a normal population with known variance σ2, a random sample (n< 30) is selected. Let...

Assume a normal population with known variance σ2, a random sample (n< 30) is selected. Let x¯,s represent the sample mean and sample deviation. (1)(2pts) write down the formula: 98% one-sided confidence interval with upper bound for the population mean. (2)(6pts) show how to derive the confidence interval formula in (1).

Consider a normal population distribution with the value of σ known.

Consider a normal population distribution with the value of σ known.(a) What is the confidence level for the interval \(\bar{x} \pm 2.81 \sigma / \sqrt{n} ?\) (Round your answer to one decimal place.) \(\%\)(b) What is the confidence level for the interval \(\bar{x} \pm 1.43 \sigma / \sqrt{n} ?\) (Round your answer to one decimal place.) \(\%\)(c) What value of \(z_{\alpha / 2}\) in the CI formula below results in a confidence level of \(99.7 \% ?\) (Round your answer...

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Let's assume our class represents a normal population with a known mean of 90 and population...

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Let's assume our class represents a normal population with a known mean of 90 and population...

Let's assume our class represents a normal population with a known mean of 95 and population...

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