solve the initial values:
if Y(3)-4Y"+20Y'=51e^3x
Y"(0)=41, Y'(0)= 11. Y(0)= 7 > solution is Y(x)= e^3x+2 e^2x
sin(4x)+6
so, what is the solution for:
Y(3)-8Y"+17Y'=12e^3x
Y"(0)=26, Y'(0)= 7. Y(0)= 6
Y(x)=???
FIND THE GENERAL SOLUTION TO THE DE: Y”’ + 4Y” – Y’ –
4Y = 0
COMPUTE:
L {7 e 3t – 5 cos ( 2t ) – 4 t 2
}
COMPUTE:
L – 1 {(3s + 6 ) / [ s ( s 2 + s – 6 ) ]
}
SOLVE THE INITIAL VALUE PROBLEM USING LAPLACE
TRANSFORMS:
Y” + 6Y’ + 5Y = 12 e t
WHEN : f ( 0 ) = -...
Power series
Find the particular solution of the differential equation:
(x^2+1)y"+xy'-4y=0 given the boundary conditions x=0, y=1 and y'=1.
Use only the 7th degree term of the solution. Solve for y at x=2.
Write your answer in whole number.