Question

In: Statistics and Probability

A beer industry association is interested in determining the preference of workers for light, dark, and...

A beer industry association is interested in determining the preference of workers for light, dark, and regular beers. A survey was conducted in which 300 blue color workers and 300 white color workers, randomly selected from two groups, were given a choice of three different beers. Each worker expressed their favorite. The following results were obtained:

Worker

Light Beer

Dark Beer

Regular Beer

Blue Color

75

50

175

White Color

120

85

95

The value of the chi-square test statistic is:

The critical value of chi-square obtained from the table (or using MS Excel) for a 5% level of significance (alpha) is:

Based on your answers to the previous questions, your decision is to Accept H0. (True or False):

Solutions

Expert Solution

Solution:

Here, we have to use chi square test for independence of two categorical variables.

Null hypothesis: H0: Two variables are independent.

Alternative hypothesis: Ha: Two variables are dependent.

We assume/given level of significance = α = 0.05

Test statistic formula is given as below:

Chi square = ∑[(O – E)^2/E]

Where, O is observed frequencies and E is expected frequencies.

E = row total * column total / Grand total

The critical value of chi-square obtained from the table (or using MS Excel) for a 5% level of significance (alpha) is:

We are given

Number of rows = r = 2

Number of columns = c = 3

Degrees of freedom = df = (r – 1)*(c – 1) = 1*2 = 2

α = 0.05

Critical value = 5.991465

(by using Chi square table or excel)

Calculation tables for test statistic are given as below:

Observed Frequencies

Beer

Color

Light

Dark

Regular

Total

Blue

75

50

175

300

While

120

85

95

300

Total

195

135

270

600

Expected Frequencies

Beer

Color

Light

Dark

Regular

Total

Blue

97.5

67.5

135

300

While

97.5

67.5

135

300

Total

195

135

270

600

Calculations

(O - E)

-22.5

-17.5

40

22.5

17.5

-40

(O - E)^2/E

5.192308

4.537037

11.85185

5.192308

4.537037

11.85185

The value of the chi-square test statistic is:

Test Statistic = Chi square = ∑[(O – E)^2/E] = 43.16239

χ2 statistic = 43.16239

P-value = 0.0000

(By using Chi square table or excel)

P-value < α = 0.05

So, we reject the null hypothesis

There is sufficient evidence to conclude that two variables are dependent.

Based on your answers to the previous questions, your decision is to Accept H0. (True or False):

Answer: False


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