In: Mechanical Engineering
(a) To determine laminar flow:
Let average density of the mixture = ? and length of the pipe = L
The average density of mixture can be found by the equation, 1/? = (0.5/?1 + 0.5/?2) = 0.5(1/?1 + 1/?2); where ?1 and ?2 are densities of 1st and 2nd fluids respectively.
Internal diameter = d, Pressure gradient = dp/dl
For laminar flow, average velocity of fluid inside pipe, uavg = -(1/8?)*(dp/dL)*(d/2)2 … (i)
Where, ? = viscosity of fluid.
From equation (i) the value of uavg can be found out.
Reynold’s number, Re = (?*uavg*d)/? …(ii)
From equation (ii) the value of Re can be found out. If Re < 2000, then the flow is laminar.
(b) Calculating the volumetric flow rate:
Area of pipe cross section, A = (?/4)*d2
Hence, volumetric flow rate, q = uavg*A = uavg*(?/4)*d2
(d) Calculating local velocity at any distance from inner wall of pipe:
For laminar flow, velocity of fluid at a perpendicular distance ‘r’ from the inner wall of the pipe,
ur = -(1/4?)*(dp/dL)*[(d/2)2 – r2]…(iii)
The equation (iii) will provide the local velocity of liquid at a given perpendicular distance from the inner wall of the pipe.