In: Physics
From the continuity equation of any volumetric flow of fluid (represented as m3 /s ) the relation of its velocity and cross sectional area through which fluid continue to flow is given as:
A1V1 = A2V2
where subscript A and V are cross sectional area and velocity respectively.
so,
1) here volumetric flow through pipe = 2.5 m3 /s and diameter of the pipe = 22 cm = 0.22 m
therefore, volumetric flow = Area x velocity
2.5 = /4 *d2 x Velocity
2.5 = /4 * 0.222 x Velocity
so, Velocity = 2.5 / ( /4 * 0.222)
= 65.76 m/s (answer)
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2) similarly, with the same volumetric flow, the diameter of the second section will be = ?
Volumetric flow = Area x velocity
2.5 = (/4 x d2 ) x velocity
2.5 = (/4 x d2 ) x 5.2
d2 = 2.5 / (5.2 * /4 )
= 0.612
or d = 0.612
= 0.782 m (answer)