Question

In: Statistics and Probability

Problem 1. A set of 25 measurements consists of the values 3 6 7 15 12...

Problem 1. A set of 25 measurements consists of the values
3 6 7 15 12
6 8 4 5 6
5 12 1 3 3
7 5 10 8 3
9 2 6 1 5
(a) Construct a relative frequency histogram to describe the data. (10 pts) (b) Find: the
median m (5 pts), the sample mean ¯x (5 pts), the sample standard deviation s (5 pts), the
upper and lower quartiles (10 pts), the 37-th percentile (5 pts). (c) Apply Tchebisheff’s
Theorem in order to estimate the proportion of measurements that lie in the interval
[¯x − (1.5)s, ¯x + (1.5)s] (10 pts).

Solutions

Expert Solution

x frequency(f) relative frequency(rf) cumulative frequency(c.f.) fx
1 2 2/25 2 2 51.6128
2 1 1/25 3 2 16.6464
3 4 4/25 7 12 37.9456
4 1 1/25 8 4 4.3264
5 4 4/25 12 20 4.6656
6 4 4/25 16 24 2.56
7 2 2/25 18 14 1.6928
8 2 2/25 20 16 7.3728
9 1 1/25 21 9 8.5264
10 1 1/25 22 10 15.3664
12 2 2/25 24 24 70.0928
15 1 1/25 25 15 79.5664

a) Histogram

b) N=25

N/2=12.5

c.f. greater than 12.5 is 16 corresponding to x=6. Thus, median is 6.

  

N/4=6.25 ; cf greater than 6.25 is 7 which corresponds to x=3. Thus, lower quartile(Q1) = 3

3N/4=18.75;   cf greater than 18.75 is 20 which corresponds to x=8. Thus, upper quartile(Q3) = 8

37N/100=9.25; cf greater than 9.25 is 12 which corresponds to x=5. Thus, 37-th percentile(P37) = 5

c) Tchebisheff's theorem is   

Thus, k=1.5

Substituting these values in tchebisheff's inequality, we get


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