In: Statistics and Probability
3 | 6 | 4 | 8 | 1 |
10 | 2 | 9 | 11 | 12 |
15 | 22 | 3 | 6 | 7 |
5 | 8 | 1 | 12 | 14 |
Each column represents a different treatment given to sick rats. Each cell is a different rat. Use statistical analysis and use post hoc testing using contrasts to find the best treatment.
Treatment 1: vitamins
Treatment 2: prescription pills
Treatment 3: brain surgery
Treatment 4: shock therapy
Treatment 5: dietary changes
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Column 1 ( vitamins ) | 4 | 33 | 8.25 | 28.91666667 | ||
Column 2 ( prescription pills ) | 4 | 38 | 9.5 | 75.66666667 | ||
Column 3 ( brain surgery ) | 4 | 17 | 4.25 | 11.58333333 | ||
Column 4 ( shock therapy ) | 4 | 37 | 9.25 | 7.583333333 | ||
Column 5 ( dietary changes ) | 4 | 34 | 8.5 | 33.66666667 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 72.7 | 4 | 18.175 | 0.577289571 | 0.683540644 | 3.055568 |
Within Groups | 472.25 | 15 | 31.4833333 | |||
Total | 544.95 | 19 |
Since we see that P-value of ANOVA test>0.05 so there is insufficient evidence that the 5 treatments are not all equal. Hence we can conclude that these 5 treatments are equally effective. Therefore we do not need to perform post hoc test.