In: Statistics and Probability
Business Statistics Assignment:
Hypothesis Testing
Multiple Parts/Steps
A. Set a target.
B. Set a tail probability that the target exceeds expectations (the
tail of the distribution beyond the UPPER/lower bounds!)
C .Calculate a z or t score (depending on....): (mean - target) /
sample standard deviation
D. Calculate the tail probability of the z or t score
E. If the tail probability of the z or t score is smaller than the
target probability, then yes your team has exceeded expectations
with a probability of being wrong equal to the tail probability of
the z or t score.
PLEASE HELP!!!!!!
The hypothesis being tested is:
H0: µd = 0
Ha: µd > 0
New | Standard |
49 | 54 |
56 | 42 |
70 | 63 |
83 | 77 |
83 | 83 |
64 | 51 |
84 | 82 |
63 | 54 |
67 | 62 |
79 | 71 |
88 | 82 |
48 | 50 |
52 | 41 |
73 | 67 |
52 | 57 |
73 | 70 |
78 | 72 |
64 | 62 |
71 | 64 |
42 | 44 |
51 | 44 |
56 | 42 |
40 | 35 |
81 | 73 |
65.292 | mean New |
60.083 | mean Standard |
5.208 | mean difference (New - Standard) |
5.340 | std. dev. |
1.090 | std. error |
24 | n |
23 | df |
4.778 | t |
0.00004 | p-value (one-tailed, upper) |
The p-value is 0.00004.
Since the p-value (0.00004) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that the new therapeutic procedure was more effective than standard treatment.