In: Statistics and Probability
Business Statistics Assignment:
Hypothesis Testing
Multiple Parts/Steps
A. Set a target.
B. Set a tail probability that the target exceeds expectations (the
tail of the distribution beyond the UPPER/lower bounds!)
C .Calculate a z or t score (depending on....): (mean - target) /
sample standard deviation
D. Calculate the tail probability of the z or t score
E. If the tail probability of the z or t score is smaller than the
target probability, then yes your team has exceeded expectations
with a probability of being wrong equal to the tail probability of
the z or t score.
PLEASE HELP!!!!!!
The hypothesis being tested is:
H0: µd = 0
Ha: µd > 0
| New | Standard | 
| 49 | 54 | 
| 56 | 42 | 
| 70 | 63 | 
| 83 | 77 | 
| 83 | 83 | 
| 64 | 51 | 
| 84 | 82 | 
| 63 | 54 | 
| 67 | 62 | 
| 79 | 71 | 
| 88 | 82 | 
| 48 | 50 | 
| 52 | 41 | 
| 73 | 67 | 
| 52 | 57 | 
| 73 | 70 | 
| 78 | 72 | 
| 64 | 62 | 
| 71 | 64 | 
| 42 | 44 | 
| 51 | 44 | 
| 56 | 42 | 
| 40 | 35 | 
| 81 | 73 | 
| 65.292 | mean New | 
| 60.083 | mean Standard | 
| 5.208 | mean difference (New - Standard) | 
| 5.340 | std. dev. | 
| 1.090 | std. error | 
| 24 | n | 
| 23 | df | 
| 4.778 | t | 
| 0.00004 | p-value (one-tailed, upper) | 
The p-value is 0.00004.
Since the p-value (0.00004) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that the new therapeutic procedure was more effective than standard treatment.