The electric field near Earth's surface points downward and has a magnitude of approximately 104 N/C....

The electric field near Earth's surface points downward and has a magnitude of approximately 104 N/C. What is the force

(F_e) on an electron due to this electric field?

magnitude= ??

Find the ratio of the magnitude of this force to the magnitude of the gravitational force

(F_g) on the electron..

Fe/ Fg=?

Expert Solution

Force on a charged particle (q) due to an electric field (E) is given by:

F = q x E

Therefore, F_e = eE = 1.602 x 10^-19 C x 104 N/C = 1.67 x 10^-17 N

Also, F_g = m_eg = 9.31 x 10^-31 kg x 9.81 m/s² = 9.13 x 10^-30 N

Thus, F_e/F_g = 1.67 x 10^-17 N / 9.13 x 10^-30 N = 1.83 x 10¹²which is the required ratio.

genius_generous answered 2 years ago

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