The electric field near the surface of Earth points downward and has a magnitude of 130...

The electric field near the surface of Earth points downward and has a magnitude of 130 N/C.

(a) Compare the upward electric force on an electron with the downward gravitational force.

____upward force/ downward force

(b) What magnitude charge should be placed on a penny of mass 6 g so that the electric force balances the weight of the penny near Earth's surface?

Solutions

Expert Solution

Force = field strength x charge on electron = 130 x e
Gravitational force = mg = electron mass x 9.81

Force/Gra. force = 130*e / me*9.81 = 130*1.6*10^-19 / 9.81*9.1*10^-31 = 208 / 89.3*10^-12

b) weight of penny = 0.006 x 9.81
Electric force = 130 x q

So q = (0.006 x 9.81)/130 = 4.527*10^-4 c

genius_generous answered 1 year ago

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