Question

In: Physics

The electric field near the surface of Earth points downward and has a magnitude of 130 N/C.

(a) Compare the upward electric force on an electron with the downward gravitational force.

(b) What magnitude charge should be placed on a penny of mass 2 g so that the electric force balances the weight of the penny near Earth?s surface? C

Expert Solution

Fe=qE

=1.6*10^-19C*150N/C

Fe=2.4*10^-17 N

Fg=mg

=-9.1*10^-31*9.8

F=-8.1*10^-30N

as we can see electric force is much bigger

b)Fe=qE

=-150Q

Fg=mg

=.002*9,8

=0.00196

=1.96*10^-2N

Fe+fg=0

(-150Q+1.96*10^-2)=0

1.96*10^-2=-150Q

Q=1.96*10^-2/150

=-0.013*10^-2

Q=-0.00013C

genius_generous answered 2 years ago

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