Question

Thirty-one small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 43.7 cases per year.

(a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)

lower limit
upper limit
margin of error

(b) Find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)

lower limit
upper limit
margin of error

(c) Find a 99% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)

lower limit
upper limit
margin of error

Answer 1

Given that

Given that,

= 138.5

= 43.7

n = 31

a ) At 90% confidence level the z is ,

= 1 - 90% = 1 - 0.90 = 0.10

/ 2 = 0.10 / 2 = 0.05

Z/2 = Z0.05 = 1.645

Margin of error = E = Z/2* (/n)

= 1.645 * (8.8 / 31 )

= 12.9

Margin of error = 12.9

At 90% confidence interval estimate of the population mean is,

- E < < + E

138.5 - 12.9< < 138.5 + 12.9

125.6 < < 151.1

Lower limit =125.6

Upper limit =151.1

b ) At 95% confidence level the z is ,

  = 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.960

Margin of error = E = Z/2* (/n)

= 1.960 * (8.8 / 31 )

= 15.4

Margin of error =15.4

At 95% confidence interval estimate of the population mean is,

- E < < + E

138.5 - 15.4 < < 138.5 + 15.4

123.1 < < 153.9

Lower limit =153.9

Upper limit =123.1

c ) At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576

Margin of error = E = Z/2* (/n)

= 2.576 * (8.8 / 31 )

= 20.2

Margin of error =20.2

At 99% confidence interval estimate of the population mean is,

- E < < + E

138.5 - 20.2 < < 138.5 +20.2

118.3 < < 65.2

Lower limit =118.3

Upper limit =158.7