Question

In: Physics

You see a vehicle move from x= +11.6m to x= +21.8m in a time of 4.76s....

You see a vehicle move from x= +11.6m to x= +21.8m in a time of 4.76s. If you know that the constant acceleration is 3.65 m/2^2 determine the initial velocity of the vehicle.

Any help is much appreciated. Thanks!

Solutions

Expert Solution

Let,

  •    : be the initial velocity
  • : be the positions of the vehicle.
  • : be the difference in position.
  •      : be the time to move from x1 to x2.
  •     : be the constant acceleration.

Given:-

Thus the distance covered by the vehicle is given by,

Now, from kinematics equation we have,

By plugging all the known values in above equation we get,

This is the initial velocity of the vehicle. The negative sign indicates that the direction of the initial velocity of the vehicle is along negative x-axis.

genius_generous answered 6 months ago
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