A downward force of 3.7N is exerted on a -5.4μC charge. (a) What is the magnitude...

A downward force of 3.7N is exerted on a -5.4μC charge. (a) What is the magnitude of the electric field at this point? (b) What is the direction of the electric field at this point?

Expert Solution

SOLUTION

Force F on a charge q in an electric field E is given by,

F=q*E

If q is +ve F is in the direction of E.

If q is -ve F is in the opposite direction of E.

Here,

a) magnitude of the electric field, E = F/q = 3.7/(5.4*10^-6) = 6.85*10⁵ N/C

b) direction of the electric field at this point is opposite to that of force i.e upward.

genius_generous answered 2 years ago

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