A magnetic field has a magnitude of 1.20 10-3 T, and an electric field has a...

A magnetic field has a magnitude of 1.20 10-3 T, and an electric field has a magnitude of 5.20 103 N/C. Both fields point in the same direction. A positive 1.8-

Expert Solution

A particle having an electric charge, q, and moving in a magnetic field ,B, with a velocity, v, experiences a force, Fb, called the Lorentz force: Fb = qvBsin(&) where '&' is the angle between the velocity direction and the magnetic field direction.

The B-field is measured in tesla, T, in SI units.

Fb = qvBsin(&) = (1.8 x 10^-6 C)(2.90 x 10^6 m/s)(1.20 x 10^-3 T) sin 90

Fb = 6.26 x 10^-3 N. in a direction perpendicular to v and B

This is the force on the charge due to the magnetic field.

The electric field produces a force on the charge of Fe = qE where

E is the strength of the electric field.

Fe = (1.8 x 10^-6 C)(5.20 x 10^3 N/C) = 9.36 x 10^-3 N. in the

direction of E.

The two forces on the charge are perpendicular to each other.

The magnitude of the net force on the charge can be determined using the pythagorean theorem:

Fnet = SQRT[Fb^2 + Fe^2] = SQRT[(6.26 x 10^-3 N.)^2 + (9.36 x 10^-3 N)^2] = 1.13 x 10^-2 N.

genius_generous answered 7 months ago

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